TSTP Solution File: ALG014+1 by Etableau---0.67

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%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : ALG014+1 : TPTP v8.1.0. Released v2.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 14 16:51:09 EDT 2022

% Result   : Theorem 0.13s 0.38s
% Output   : CNFRefutation 0.13s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    5
% Syntax   : Number of formulae    :   14 (   7 unt;   0 def)
%            Number of atoms       :   95 (  84 equ)
%            Maximal formula atoms :   32 (   6 avg)
%            Number of connectives :   97 (  16   ~;  23   |;  57   &)
%                                         (   1 <=>;   0  =>;   0  <=;   0 <~>)
%            Maximal formula depth :   12 (   5 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   1 usr;   2 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn   0   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(co1,conjecture,
    ( ( op(e0,e0) = e0
      & op(e1,e1) = e0
      & op(e2,e2) = e0
      & op(e3,e3) = e0 )
    | ( op(e0,e0) = e1
      & op(e1,e1) = e1
      & op(e2,e2) = e1
      & op(e3,e3) = e1 )
    | ( op(e0,e0) = e2
      & op(e1,e1) = e2
      & op(e2,e2) = e2
      & op(e3,e3) = e2 )
    | ( op(e0,e0) = e3
      & op(e1,e1) = e3
      & op(e2,e2) = e3
      & op(e3,e3) = e3 )
    | ~ ( ( op(e0,e0) = e0
          & op(e1,e1) = e0
          & op(e2,e2) = e0
          & op(e3,e3) = e0 )
        | ( op(e0,e0) = e1
          & op(e1,e1) = e1
          & op(e2,e2) = e1
          & op(e3,e3) = e1 )
        | ( op(e0,e0) = e2
          & op(e1,e1) = e2
          & op(e2,e2) = e2
          & op(e3,e3) = e2 )
        | ( op(e0,e0) = e3
          & op(e1,e1) = e3
          & op(e2,e2) = e3
          & op(e3,e3) = e3 ) ) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',co1) ).

fof(ax3,axiom,
    ( op(unit,e0) = e0
    & op(e0,unit) = e0
    & op(unit,e1) = e1
    & op(e1,unit) = e1
    & op(unit,e2) = e2
    & op(e2,unit) = e2
    & op(unit,e3) = e3
    & op(e3,unit) = e3
    & ( unit = e0
      | unit = e1
      | unit = e2
      | unit = e3 ) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',ax3) ).

fof(ax5,axiom,
    unit = e0,
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',ax5) ).

fof(ax11,axiom,
    ( e0 != e1
    & e0 != e2
    & e0 != e3
    & e1 != e2
    & e1 != e3
    & e2 != e3 ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',ax11) ).

fof(c_0_4,plain,
    ( epred1_0
  <=> ( ( op(e0,e0) = e0
        & op(e1,e1) = e0
        & op(e2,e2) = e0
        & op(e3,e3) = e0 )
      | ( op(e0,e0) = e1
        & op(e1,e1) = e1
        & op(e2,e2) = e1
        & op(e3,e3) = e1 )
      | ( op(e0,e0) = e2
        & op(e1,e1) = e2
        & op(e2,e2) = e2
        & op(e3,e3) = e2 ) ) ),
    introduced(definition) ).

fof(c_0_5,negated_conjecture,
    ~ ( epred1_0
      | ( op(e0,e0) = e3
        & op(e1,e1) = e3
        & op(e2,e2) = e3
        & op(e3,e3) = e3 )
      | ~ ( epred1_0
          | ( op(e0,e0) = e3
            & op(e1,e1) = e3
            & op(e2,e2) = e3
            & op(e3,e3) = e3 ) ) ),
    inference(apply_def,[status(thm)],[inference(apply_def,[status(thm)],[inference(assume_negation,[status(cth)],[co1]),c_0_4]),c_0_4]) ).

fof(c_0_6,negated_conjecture,
    ( ~ epred1_0
    & ( op(e0,e0) != e3
      | op(e1,e1) != e3
      | op(e2,e2) != e3
      | op(e3,e3) != e3 )
    & ( op(e0,e0) = e3
      | epred1_0 )
    & ( op(e1,e1) = e3
      | epred1_0 )
    & ( op(e2,e2) = e3
      | epred1_0 )
    & ( op(e3,e3) = e3
      | epred1_0 ) ),
    inference(distribute,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_5])]) ).

cnf(c_0_7,plain,
    op(e0,unit) = e0,
    inference(split_conjunct,[status(thm)],[ax3]) ).

cnf(c_0_8,plain,
    unit = e0,
    inference(split_conjunct,[status(thm)],[ax5]) ).

cnf(c_0_9,negated_conjecture,
    ( op(e0,e0) = e3
    | epred1_0 ),
    inference(split_conjunct,[status(thm)],[c_0_6]) ).

cnf(c_0_10,plain,
    op(e0,e0) = e0,
    inference(rw,[status(thm)],[c_0_7,c_0_8]) ).

cnf(c_0_11,plain,
    e0 != e3,
    inference(split_conjunct,[status(thm)],[ax11]) ).

cnf(c_0_12,negated_conjecture,
    ~ epred1_0,
    inference(split_conjunct,[status(thm)],[c_0_6]) ).

cnf(c_0_13,negated_conjecture,
    $false,
    inference(sr,[status(thm)],[inference(sr,[status(thm)],[inference(rw,[status(thm)],[c_0_9,c_0_10]),c_0_11]),c_0_12]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : ALG014+1 : TPTP v8.1.0. Released v2.7.0.
% 0.12/0.13  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.13/0.34  % Computer : n023.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Wed Jun  8 02:57:38 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.13/0.38  # No SInE strategy applied
% 0.13/0.38  # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.13/0.38  # and selection function SelectComplexExceptUniqMaxHorn.
% 0.13/0.38  #
% 0.13/0.38  # Presaturation interreduction done
% 0.13/0.38  
% 0.13/0.38  # Proof found!
% 0.13/0.38  # SZS status Theorem
% 0.13/0.38  # SZS output start CNFRefutation
% See solution above
% 0.13/0.38  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------