TPTP Problem File: SWB050+1.p
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%------------------------------------------------------------------------------
% File : SWB050+1 : TPTP v9.0.0. Released v5.2.0.
% Domain : Semantic Web
% Problem : Symmetric Property Extensional
% Version : [Sch11] axioms.
% English : If the extension of a property is symmetric, then the property
% itself is.
% Refs : [Sch11] Schneider, M. (2011), Email to G. Sutcliffe
% Source : [Sch11]
% Names : rdfbased-sem-char-symmetric-ext [Sch11]
% Status : Theorem
% Rating : 0.82 v9.0.0, 0.78 v8.2.0, 0.86 v8.1.0, 0.78 v7.5.0, 0.84 v7.4.0, 0.80 v7.3.0, 0.83 v7.1.0, 0.78 v7.0.0, 0.83 v6.4.0, 0.81 v6.3.0, 0.79 v6.2.0, 0.88 v6.1.0, 0.90 v6.0.0, 0.87 v5.5.0, 0.93 v5.4.0, 0.96 v5.2.0
% Syntax : Number of formulae : 560 ( 197 unt; 0 def)
% Number of atoms : 1789 ( 90 equ)
% Maximal formula atoms : 32 ( 3 avg)
% Number of connectives : 1365 ( 136 ~; 35 |; 773 &)
% ( 126 <=>; 295 =>; 0 <=; 0 <~>)
% Maximal formula depth : 27 ( 5 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 13 ( 12 usr; 1 prp; 0-3 aty)
% Number of functors : 160 ( 160 usr; 159 con; 0-2 aty)
% Number of variables : 979 ( 911 !; 68 ?)
% SPC : FOF_THM_RFO_SEQ
% Comments :
%------------------------------------------------------------------------------
%----Include OWL 2 Full axioms
include('Axioms/SWB001+0.ax').
%------------------------------------------------------------------------------
fof(conclusion_rdfbased_sem_char_symmetric_ext,conjecture,
iext(uri_rdf_type,uri_ex_p,uri_owl_SymmetricProperty) ).
fof(premise_rdfbased_sem_char_symmetric_ext,axiom,
? [X0,X2,X3,X5,X1,X4] :
( iext(uri_rdfs_domain,uri_ex_p,X0)
& iext(uri_rdfs_range,uri_ex_p,X1)
& iext(uri_owl_oneOf,X0,X2)
& iext(uri_owl_oneOf,X1,X3)
& iext(uri_ex_p,uri_ex_x,uri_ex_y)
& iext(uri_ex_p,uri_ex_x,uri_ex_x)
& iext(uri_rdf_first,X2,uri_ex_x)
& iext(uri_rdf_rest,X2,X4)
& iext(uri_rdf_first,X5,uri_ex_y)
& iext(uri_rdf_rest,X5,uri_rdf_nil)
& iext(uri_ex_p,uri_ex_y,uri_ex_x)
& iext(uri_ex_p,uri_ex_y,uri_ex_y)
& iext(uri_rdf_first,X4,uri_ex_y)
& iext(uri_rdf_rest,X4,uri_rdf_nil)
& iext(uri_rdf_first,X3,uri_ex_x)
& iext(uri_rdf_rest,X3,X5) ) ).
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