## TPTP Problem File: SWB050+1.p

View Solutions - Solve Problem

```%------------------------------------------------------------------------------
% File     : SWB050+1 : TPTP v7.5.0. Released v5.2.0.
% Domain   : Semantic Web
% Problem  : Symmetric Property Extensional
% Version  : [Sch11] axioms.
% English  : If the extension of a property is symmetric, then the property
%            itself is.

% Refs     : [Sch11] Schneider, M. (2011), Email to G. Sutcliffe
% Source   : [Sch11]
% Names    : rdfbased-sem-char-symmetric-ext [Sch11]

% Status   : Theorem
% Rating   : 0.78 v7.5.0, 0.84 v7.4.0, 0.80 v7.3.0, 0.83 v7.1.0, 0.78 v7.0.0, 0.83 v6.4.0, 0.81 v6.3.0, 0.79 v6.2.0, 0.88 v6.1.0, 0.90 v6.0.0, 0.87 v5.5.0, 0.93 v5.4.0, 0.96 v5.2.0
% Syntax   : Number of formulae    :  560 ( 197 unit)
%            Number of atoms       : 1789 (  90 equality)
%            Maximal formula depth :   27 (   5 average)
%            Number of connectives : 1365 ( 136   ~;  35   |; 773   &)
%                                         ( 126 <=>; 295  =>;   0  <=;   0 <~>)
%                                         (   0  ~|;   0  ~&)
%            Number of predicates  :   13 (   1 propositional; 0-3 arity)
%            Number of functors    :  160 ( 159 constant; 0-2 arity)
%            Number of variables   :  979 (   0 sgn; 911   !;  68   ?)
%            Maximal term depth    :    2 (   1 average)
% SPC      : FOF_THM_RFO_SEQ

%------------------------------------------------------------------------------
%----Include OWL 2 Full axioms
include('Axioms/SWB001+0.ax').
%------------------------------------------------------------------------------
fof(conclusion_rdfbased_sem_char_symmetric_ext,conjecture,(
iext(uri_rdf_type,uri_ex_p,uri_owl_SymmetricProperty) )).

fof(premise_rdfbased_sem_char_symmetric_ext,axiom,(
? [X0,X2,X3,X5,X1,X4] :
( iext(uri_rdfs_domain,uri_ex_p,X0)
& iext(uri_rdfs_range,uri_ex_p,X1)
& iext(uri_owl_oneOf,X0,X2)
& iext(uri_owl_oneOf,X1,X3)
& iext(uri_ex_p,uri_ex_x,uri_ex_y)
& iext(uri_ex_p,uri_ex_x,uri_ex_x)
& iext(uri_rdf_first,X2,uri_ex_x)
& iext(uri_rdf_rest,X2,X4)
& iext(uri_rdf_first,X5,uri_ex_y)
& iext(uri_rdf_rest,X5,uri_rdf_nil)
& iext(uri_ex_p,uri_ex_y,uri_ex_x)
& iext(uri_ex_p,uri_ex_y,uri_ex_y)
& iext(uri_rdf_first,X4,uri_ex_y)
& iext(uri_rdf_rest,X4,uri_rdf_nil)
& iext(uri_rdf_first,X3,uri_ex_x)
& iext(uri_rdf_rest,X3,X5) ) )).

%------------------------------------------------------------------------------
```