%--------------------------------------------------------------------------
% File     : SET773+4 : TPTP v8.2.0. Released v2.2.0.
% Domain   : Set Theory (Equivalence relations)
% Problem  : Intersection of equivalence relations is an equivalence relation
% Version  : [Pas99] axioms.
% English  :

% Refs     : [Pas99] Pastre (1999), Email to G. Sutcliffe
% Source   : [Pas99]
% Names    :

% Status   : Theorem
% Rating   : 0.56 v8.2.0, 0.64 v8.1.0, 0.61 v7.5.0, 0.56 v7.4.0, 0.57 v7.3.0, 0.55 v7.2.0, 0.52 v7.1.0, 0.48 v7.0.0, 0.60 v6.4.0, 0.62 v6.3.0, 0.54 v6.2.0, 0.52 v6.1.0, 0.57 v6.0.0, 0.65 v5.5.0, 0.70 v5.4.0, 0.82 v5.3.0, 0.81 v5.2.0, 0.80 v5.1.0, 0.81 v5.0.0, 0.79 v4.1.0, 0.78 v4.0.1, 0.87 v4.0.0, 0.88 v3.7.0, 0.75 v3.5.0, 0.79 v3.4.0, 0.84 v3.3.0, 0.64 v3.2.0, 0.91 v3.1.0, 0.89 v2.7.0, 0.83 v2.6.0, 0.86 v2.5.0, 0.88 v2.4.0, 0.75 v2.3.0, 0.67 v2.2.1
% Syntax   : Number of formulae    :   17 (   1 unt;   0 def)
%            Number of atoms       :   76 (   4 equ)
%            Maximal formula atoms :   13 (   4 avg)
%            Number of connectives :   62 (   3   ~;   2   |;  25   &)
%                                         (  16 <=>;  16  =>;   0  <=;   0 <~>)
%            Maximal formula depth :   13 (   7 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    9 (   8 usr;   0 prp; 2-3 aty)
%            Number of functors    :   10 (  10 usr;   1 con; 0-3 aty)
%            Number of variables   :   63 (  59   !;   4   ?)
% SPC      : FOF_THM_RFO_SEQ

% Comments :
%--------------------------------------------------------------------------
%----Include set theory definitions
include('Axioms/SET006+0.ax').
%----Include equivalence relation axioms
include('Axioms/SET006+2.ax').
%--------------------------------------------------------------------------
fof(thIII09,conjecture,
    ! [E,R1,R2,R] :
      ( ( equivalence(R1,E)
        & equivalence(R2,E)
        & ! [A,B] :
            ( ( member(A,E)
              & member(B,E) )
           => ( apply(R,A,B)
            <=> ( apply(R1,A,B)
                & apply(R2,A,B) ) ) ) )
     => equivalence(R,E) ) ).

%--------------------------------------------------------------------------