TPTP Problem File: SET683^3.p

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%------------------------------------------------------------------------------
% File     : SET683^3 : TPTP v9.0.0. Released v3.6.0.
% Domain   : Set Theory
% Problem  : !y in E : y in range of R (X to Y) ?x in D : x in domain of R
% Version  : [BS+08] axioms.
% English  : For every element y in E such that y is in the range in a relation %            R from X to Y there exists an element x in D such that x is in the %            domain of R.

% Refs     : [BS+05] Benzmueller et al. (2005), Can a Higher-Order and a Fi
%          : [BS+08] Benzmueller et al. (2008), Combined Reasoning by Autom
%          : [Ben08] Benzmueller (2008), Email to Geoff Sutcliffe
% Source   : [Ben08]
% Names    :

% Status   : Theorem
% Rating   : 0.12 v9.0.0, 0.20 v8.2.0, 0.31 v8.1.0, 0.09 v7.5.0, 0.00 v7.4.0, 0.11 v7.2.0, 0.00 v7.1.0, 0.12 v7.0.0, 0.14 v6.4.0, 0.17 v6.3.0, 0.20 v6.2.0, 0.00 v6.1.0, 0.14 v5.5.0, 0.17 v5.4.0, 0.20 v4.1.0, 0.33 v3.7.0
% Syntax   : Number of formulae    :   71 (  35 unt;  35 typ;  35 def)
%            Number of atoms       :   89 (  43 equ;   0 cnn)
%            Maximal formula atoms :    3 (   2 avg)
%            Number of connectives :  137 (   8   ~;   5   |;  19   &;  92   @)
%                                         (   1 <=>;  12  =>;   0  <=;   0 <~>)
%            Maximal formula depth :   12 (   1 avg)
%            Number of types       :    2 (   0 usr)
%            Number of type conns  :  216 ( 216   >;   0   *;   0   +;   0  <<)
%            Number of symbols     :   40 (  38 usr;   4 con; 0-4 aty)
%            Number of variables   :  112 (  80   ^;  23   !;   9   ?; 112   :)
% SPC      : TH0_THM_EQU_NAR

% Comments : 
%------------------------------------------------------------------------------
%----Include basic set theory definitions
include('Axioms/SET008^0.ax').
%----Include definitions for relations
include('Axioms/SET008^2.ax').
%------------------------------------------------------------------------------
thf(thm,conjecture,
    ! [R: $i > $i > $o,X: $i > $o,Y: $i > $o] :
      ( ( is_rel_on @ R @ X @ Y )
     => ! [V: $i] :
          ( ( Y @ V )
         => ( ( rel_codomain @ R @ V )
           => ? [U: $i] :
                ( ( X @ U )
                & ( rel_domain @ R @ U ) ) ) ) ) ).

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