TPTP Problem File: ROB018-10.p
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% File : ROB018-10 : TPTP v9.0.0. Released v7.5.0.
% Domain : Puzzles
% Problem : If -(d + e) = -e then e + 2(d + -(d + -e)) absorbs d + -(d + -e)
% Version : Especial.
% English :
% Refs : [CS18] Claessen & Smallbone (2018), Efficient Encodings of Fi
% : [Sma18] Smallbone (2018), Email to Geoff Sutcliffe
% Source : [Sma18]
% Names :
% Status : Unsatisfiable
% Rating : 0.91 v8.2.0, 0.92 v8.1.0, 0.95 v7.5.0
% Syntax : Number of clauses : 11 ( 11 unt; 0 nHn; 3 RR)
% Number of literals : 11 ( 11 equ; 1 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 7 ( 2 avg)
% Number of predicates : 1 ( 0 usr; 0 prp; 2-2 aty)
% Number of functors : 11 ( 11 usr; 4 con; 0-4 aty)
% Number of variables : 17 ( 2 sgn)
% SPC : CNF_UNS_RFO_PEQ_UEQ
% Comments : Converted from ROB018-1 to UEQ using [CS18].
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cnf(ifeq_axiom,axiom,
ifeq2(A,A,B,C) = B ).
cnf(ifeq_axiom_001,axiom,
ifeq(A,A,B,C) = B ).
cnf(commutativity_of_add,axiom,
add(X,Y) = add(Y,X) ).
cnf(associativity_of_add,axiom,
add(add(X,Y),Z) = add(X,add(Y,Z)) ).
cnf(robbins_axiom,axiom,
negate(add(negate(add(X,Y)),negate(add(X,negate(Y))))) = X ).
cnf(one_times_x,axiom,
multiply(one,X) = X ).
cnf(times_by_adding,axiom,
ifeq2(positive_integer(X),true,add(X,multiply(V,X)),multiply(successor(V),X)) = multiply(successor(V),X) ).
cnf(one,axiom,
positive_integer(one) = true ).
cnf(next_integer,axiom,
ifeq(positive_integer(X),true,positive_integer(successor(X)),true) = true ).
cnf(condition,hypothesis,
negate(add(d,negate(e))) = negate(e) ).
cnf(prove_result,negated_conjecture,
add(e,multiply(successor(successor(one)),add(d,negate(add(d,negate(e)))))) != add(e,multiply(successor(one),add(d,negate(add(d,negate(e)))))) ).
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