## TPTP Problem File: ROB018-10.p

View Solutions - Solve Problem

```%------------------------------------------------------------------------------
% File     : ROB018-10 : TPTP v7.5.0. Released v7.5.0.
% Domain   : Puzzles
% Problem  : If -(d + e) = -e then e + 2(d + -(d + -e)) absorbs d + -(d + -e)
% Version  : Especial.
% English  :

% Refs     : [CS18]  Claessen & Smallbone (2018), Efficient Encodings of Fi
%          : [Sma18] Smallbone (2018), Email to Geoff Sutcliffe
% Source   : [Sma18]
% Names    :

% Status   : Unsatisfiable
% Rating   : 0.95 v7.5.0
% Syntax   : Number of clauses     :   11 (   0 non-Horn;  11 unit;   3 RR)
%            Number of atoms       :   11 (  11 equality)
%            Maximal clause size   :    1 (   1 average)
%            Number of predicates  :    1 (   0 propositional; 2-2 arity)
%            Number of functors    :   11 (   4 constant; 0-4 arity)
%            Number of variables   :   17 (   2 singleton)
%            Maximal term depth    :    7 (   3 average)
% SPC      : CNF_UNS_RFO_PEQ_UEQ

% Comments : Converted from ROB018-1 to UEQ using [CS18].
%------------------------------------------------------------------------------
cnf(ifeq_axiom,axiom,
( ifeq2(A,A,B,C) = B )).

cnf(ifeq_axiom_001,axiom,
( ifeq(A,A,B,C) = B )).

cnf(robbins_axiom,axiom,

cnf(one_times_x,axiom,
( multiply(one,X) = X )).

cnf(one,axiom,
( positive_integer(one) = true )).

cnf(next_integer,axiom,
( ifeq(positive_integer(X),true,positive_integer(successor(X)),true) = true )).

cnf(condition,hypothesis,