TPTP Problem File: ROB007-4.p
View Solutions
- Solve Problem
%--------------------------------------------------------------------------
% File : ROB007-4 : TPTP v8.2.0. Bugfixed v3.1.0.
% Domain : Robbins Algebra
% Problem : Absorbed within negation element => Exists idempotent element
% Version : [Win90] (equality) axioms : Augmented.
% English : If there exist a, b such that -(a+b) = -b, then the algebra
% is Boolean.
% Refs : [HMT71] Henkin et al. (1971), Cylindrical Algebras
% : [Win90] Winker (1990), Robbins Algebra: Conditions that make a
% Source : [Win90]
% Names : Theorem 1.2 [Win90]
% Status : Unknown
% Rating : 1.00 v3.1.0
% Syntax : Number of clauses : 12 ( 8 unt; 0 nHn; 7 RR)
% Number of literals : 16 ( 12 equ; 6 neg)
% Maximal clause size : 2 ( 1 avg)
% Maximal term depth : 7 ( 2 avg)
% Number of predicates : 2 ( 1 usr; 0 prp; 1-2 aty)
% Number of functors : 7 ( 7 usr; 3 con; 0-2 aty)
% Number of variables : 18 ( 1 sgn)
% SPC : CNF_UNK_RFO_SEQ_HRN
% Comments : Commutativity, associativity, and Huntington's axiom
% axiomatize Boolean algebra.
% : The two extra lemmas are suggested by [Win90].
% Bugfixes : v3.1.0 - Removed extra negated_conjecture clauses.
%--------------------------------------------------------------------------
%----Include axioms for Robbins algebra
include('Axioms/ROB001-0.ax').
%----Include axioms for numbers in Robbins algebras
include('Axioms/ROB001-1.ax').
%--------------------------------------------------------------------------
cnf(absorbtion,axiom,
add(X,Y) != Y ).
cnf(corollary_3_9_1,axiom,
( negate(add(X,negate(Y))) != negate(Y)
| add(Y,multiply(successor(successor(one)),add(X,negate(add(X,negate(Y)))))) = add(Y,multiply(successor(one),add(X,negate(add(X,negate(Y)))))) ) ).
cnf(corollary_3_9_2,axiom,
( negate(add(negate(Y),negate(add(X,negate(Y))))) != X
| add(Y,multiply(successor(successor(one)),add(X,negate(add(X,negate(Y)))))) = add(Y,multiply(successor(one),add(X,negate(add(X,negate(Y)))))) ) ).
cnf(condition,hypothesis,
negate(add(a,b)) = negate(b) ).
cnf(prove_idempotence,negated_conjecture,
add(X,X) != X ).
%--------------------------------------------------------------------------