TPTP Problem File: PUZ155_1.p
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% File : PUZ155_1 : TPTP v9.2.0. Released v9.1.0.
% Domain : Puzzles
% Problem : Infinite descendants
% Version : Especial.
% English :
% Refs :
% Source : [TPTP]
% Names :
% Status : Satisfiable
% Rating : 0.67 v9.1.0
% Syntax : Number of formulae : 8 ( 2 unt; 4 typ; 0 def)
% Number of atoms : 7 ( 2 equ)
% Maximal formula atoms : 3 ( 1 avg)
% Number of connectives : 4 ( 1 ~; 0 |; 1 &)
% ( 0 <=>; 2 =>; 0 <=; 0 <~>)
% Maximal formula depth : 6 ( 4 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of types : 2 ( 1 usr)
% Number of type conns : 3 ( 2 >; 1 *; 0 +; 0 <<)
% Number of predicates : 2 ( 1 usr; 0 prp; 2-2 aty)
% Number of functors : 2 ( 2 usr; 1 con; 0-1 aty)
% Number of variables : 8 ( 7 !; 1 ?; 8 :)
% SPC : TF0_CSA_EQU_NAR
% Comments :
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tff(person_type,type,
person: $tType ).
tff(bob_decl,type,
bob: person ).
tff(child_of_decl,type,
child_of: person > person ).
tff(is_descendant_decl,type,
is_descendant: ( person * person ) > $o ).
tff(descendents_different,axiom,
! [A: person,D: person] :
( is_descendant(A,D)
=> ( A != D ) ) ).
tff(descendent_transitive,axiom,
! [A: person,C: person,G: person] :
( ( is_descendant(A,C)
& is_descendant(C,G) )
=> is_descendant(A,G) ) ).
tff(child_is_descendant,axiom,
! [P: person] : is_descendant(P,child_of(P)) ).
tff(all_have_child,axiom,
! [P: person] :
? [C: person] : ( C = child_of(P) ) ).
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