TPTP Problem File: PUZ065+1.p

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%------------------------------------------------------------------------------
% File     : PUZ065+1 : TPTP v9.0.0. Released v3.2.0.
% Domain   : Puzzles
% Problem  : Sudoku 13273
% Version  : Especial.
% English  :

% Refs     : [Hill06] Hillenbrand (2006), Email to G. Sutcliffe
% Source   : [Hill06]
% Names    :

% Status   : Satisfiable
% Rating   : 0.17 v9.0.0, 0.40 v8.2.0, 0.33 v8.1.0, 0.25 v7.5.0, 0.33 v7.4.0, 0.00 v7.1.0, 0.25 v7.0.0, 0.00 v6.4.0, 0.60 v6.2.0, 0.50 v6.1.0, 0.60 v6.0.0, 0.50 v5.5.0, 0.00 v5.0.0, 0.33 v4.0.1, 0.75 v3.7.0, 0.33 v3.4.0, 0.40 v3.3.0, 0.00 v3.2.0
% Syntax   : Number of formulae    :  370 (  18 unt;   0 def)
%            Number of atoms       : 3942 (3941 equ)
%            Maximal formula atoms :   36 (  10 avg)
%            Number of connectives : 4580 (1008   ~;2592   |; 980   &)
%                                         (   0 <=>;   0  =>;   0  <=;   0 <~>)
%            Maximal formula depth :   37 (  11 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   0 prp; 2-81 aty)
%            Number of functors    :   10 (  10 usr;   9 con; 0-2 aty)
%            Number of variables   :    0 (   0   !;   0   ?)
% SPC      : FOF_SAT_RFO_SEQ

% Comments : The hardest for SPASS for saturation.
%------------------------------------------------------------------------------
%----Include Sudoku axioms
include('Axioms/PUZ005+0.ax').
%------------------------------------------------------------------------------
%----Preset values
fof(ax353,axiom,
    ssA(n1,n2) = n1 ).

fof(ax354,axiom,
    ssA(n1,n9) = n9 ).

fof(ax355,axiom,
    ssA(n2,n4) = n3 ).

fof(ax356,axiom,
    ssA(n2,n7) = n8 ).

fof(ax357,axiom,
    ssA(n3,n7) = n6 ).

fof(ax358,axiom,
    ssA(n4,n5) = n1 ).

fof(ax359,axiom,
    ssA(n4,n6) = n2 ).

fof(ax360,axiom,
    ssA(n4,n7) = n4 ).

fof(ax361,axiom,
    ssA(n5,n1) = n7 ).

fof(ax362,axiom,
    ssA(n5,n3) = n3 ).

fof(ax363,axiom,
    ssA(n6,n1) = n5 ).

fof(ax364,axiom,
    ssA(n7,n1) = n8 ).

fof(ax365,axiom,
    ssA(n7,n4) = n6 ).

fof(ax366,axiom,
    ssA(n8,n5) = n4 ).

fof(ax367,axiom,
    ssA(n8,n8) = n2 ).

fof(ax368,axiom,
    ssA(n9,n4) = n7 ).

fof(ax369,axiom,
    ssA(n9,n8) = n5 ).

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