TPTP Problem File: LCL660+1.001.p
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- Solve Problem
%------------------------------------------------------------------------------
% File : LCL660+1.001 : TPTP v9.0.0. Released v4.0.0.
% Domain : Logic Calculi (Modal Logic)
% Problem : In KT, box Grz & Grz{C() & A4{C()/p0}/p0} -> Grz1, size 1
% Version : Especial.
% English :
% Refs : [BHS00] Balsiger et al. (2000), A Benchmark Method for the Pro
% : [Kam08] Kaminski (2008), Email to G. Sutcliffe
% Source : [Kam08]
% Names : kt_grz_p [BHS00]
% Status : Theorem
% Rating : 0.40 v9.0.0, 0.25 v8.2.0, 0.47 v8.1.0, 0.36 v7.5.0, 0.43 v7.4.0, 0.31 v7.3.0, 0.29 v7.2.0, 0.33 v7.1.0, 0.25 v7.0.0, 0.29 v6.4.0, 0.50 v6.3.0, 0.38 v6.2.0, 0.45 v6.1.0, 0.60 v6.0.0, 0.25 v5.5.0, 0.71 v5.4.0, 0.65 v5.3.0, 0.74 v5.2.0, 0.64 v5.0.0, 0.80 v4.1.0, 0.83 v4.0.1, 0.84 v4.0.0
% Syntax : Number of formulae : 2 ( 1 unt; 0 def)
% Number of atoms : 121 ( 0 equ)
% Maximal formula atoms : 120 ( 60 avg)
% Number of connectives : 235 ( 116 ~; 112 |; 7 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 37 ( 20 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 5 ( 5 usr; 0 prp; 1-2 aty)
% Number of functors : 0 ( 0 usr; 0 con; --- aty)
% Number of variables : 64 ( 63 !; 1 ?)
% SPC : FOF_THM_RFO_NEQ
% Comments : A naive relational encoding of the modal logic problem into
% first-order logic.
%------------------------------------------------------------------------------
fof(reflexivity,axiom,
! [X] : r1(X,X) ).
fof(main,conjecture,
~ ? [X] :
~ ( ( ~ ! [Y] :
( ~ r1(X,Y)
| ~ p3(Y) )
& ( ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) ) )
| ! [Y] :
( ~ r1(X,Y)
| p4(Y) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p4(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p4(Y) )
| ~ p4(X) ) )
| ( ~ ! [Y] :
( ~ r1(X,Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ~ p3(X) ) )
& ( ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) ) )
| ! [Y] :
( ~ r1(X,Y)
| p1(Y) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p1(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p1(Y) )
| ~ p1(X) ) )
| ~ ( ( ( ( ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
& ( p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
| ~ ! [Y] :
( ~ r1(X,Y)
| ( ( ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
| ~ ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
& ( p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| ( ( ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
| ~ ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
& ( p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) ) )
| ~ ( ( ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
& ( p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) ) ) ) )
& ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) ) ) ) ).
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