TPTP Problem File: GRP102-1.p

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%--------------------------------------------------------------------------
% File     : GRP102-1 : TPTP v8.2.0. Bugfixed v2.7.0.
% Domain   : Group Theory (Abelian)
% Problem  : Single axiom for Abelian group theory, in double div and id
% Version  : [McC93] (equality) axioms.
% English  : This is a single axiom for Abelian group theory, in terms
%            of double division and identity.

% Refs     : [McC93] McCune (1993), Single Axioms for Groups and Abelian Gr
% Source   : [McC93]
% Names    : Axiom 3.11.4 [McC93]

% Status   : Unsatisfiable
% Rating   : 0.27 v8.2.0, 0.31 v8.1.0, 0.21 v7.5.0, 0.29 v7.4.0, 0.35 v7.3.0, 0.23 v7.2.0, 0.25 v7.1.0, 0.18 v7.0.0, 0.23 v6.4.0, 0.36 v6.3.0, 0.20 v6.2.0, 0.30 v6.1.0, 0.27 v6.0.0, 0.29 v5.5.0, 0.38 v5.4.0, 0.22 v5.3.0, 0.40 v5.2.0, 0.25 v5.1.0, 0.22 v5.0.0, 0.30 v4.1.0, 0.22 v4.0.1, 0.25 v4.0.0, 0.14 v3.7.0, 0.00 v3.3.0, 0.22 v3.2.0, 0.11 v3.1.0, 0.00 v2.7.0
% Syntax   : Number of clauses     :    5 (   4 unt;   0 nHn;   1 RR)
%            Number of literals    :    8 (   8 equ;   4 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    6 (   2 avg)
%            Number of predicates  :    1 (   0 usr;   0 prp; 2-2 aty)
%            Number of functors    :   11 (  11 usr;   8 con; 0-2 aty)
%            Number of variables   :    7 (   0 sgn)
% SPC      : CNF_UNS_RFO_PEQ_NUE

% Comments :
% Bugfixes : v2.3.0 - Deleted double_division, added multiply and inverse,
%            fixed prove_these_axioms.
%          : v2.7.0 - Grounded conjecture
%--------------------------------------------------------------------------
cnf(single_axiom,axiom,
    double_divide(double_divide(X,double_divide(double_divide(double_divide(Y,X),Z),double_divide(Y,identity))),double_divide(identity,identity)) = Z ).

%----Definition of multiply
cnf(multiply,axiom,
    multiply(X,Y) = double_divide(double_divide(Y,X),identity) ).

%----Definition of inverse
cnf(inverse,axiom,
    inverse(X) = double_divide(X,identity) ).

%----Definition of identity
cnf(identity,axiom,
    identity = double_divide(X,inverse(X)) ).

cnf(prove_these_axioms,negated_conjecture,
    ( multiply(inverse(a1),a1) != identity
    | multiply(identity,a2) != a2
    | multiply(multiply(a3,b3),c3) != multiply(a3,multiply(b3,c3))
    | multiply(a4,b4) != multiply(b4,a4) ) ).

%--------------------------------------------------------------------------