TPTP Problem File: GRA011+1.p
View Solutions
- Solve Problem
%--------------------------------------------------------------------------
% File : GRA011+1 : TPTP v9.0.0. Bugfixed v3.2.0.
% Domain : Graph Theory
% Problem : Maximal shortest path length in terms of triangles
% Version : Especial.
% English : In a complete graph, if there is a shortest path P from V1 to
% V2, then the number of sequential pairs in P is the number of
% triangles in P.
% Refs :
% Source : [TPTP]
% Names :
% Status : Theorem
% Rating : 0.73 v9.0.0, 0.72 v8.1.0, 0.67 v7.5.0, 0.72 v7.4.0, 0.67 v7.3.0, 0.69 v7.2.0, 0.66 v7.1.0, 0.70 v7.0.0, 0.77 v6.4.0, 0.73 v6.3.0, 0.71 v6.2.0, 0.80 v6.1.0, 0.87 v6.0.0, 0.78 v5.5.0, 0.85 v5.4.0, 0.86 v5.3.0, 0.85 v5.1.0, 0.86 v5.0.0, 0.83 v4.1.0, 0.87 v4.0.1, 0.91 v4.0.0, 0.92 v3.7.0, 0.95 v3.3.0, 0.93 v3.2.0
% Syntax : Number of formulae : 18 ( 1 unt; 0 def)
% Number of atoms : 93 ( 25 equ)
% Maximal formula atoms : 9 ( 5 avg)
% Number of connectives : 81 ( 6 ~; 3 |; 46 &)
% ( 3 <=>; 18 =>; 2 <=; 3 <~>)
% Maximal formula depth : 13 ( 9 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 12 ( 11 usr; 1 prp; 0-3 aty)
% Number of functors : 12 ( 12 usr; 6 con; 0-2 aty)
% Number of variables : 68 ( 58 !; 10 ?)
% SPC : FOF_THM_RFO_SEQ
% Comments :
% Bugfixes : v3.2.0 - Bugfix to GRA001+0.ax
%--------------------------------------------------------------------------
%----Include axioms for directed graphs and paths
include('Axioms/GRA001+0.ax').
%--------------------------------------------------------------------------
fof(triangle_defn,axiom,
! [E1,E2,E3] :
( triangle(E1,E2,E3)
<=> ( edge(E1)
& edge(E2)
& edge(E3)
& sequential(E1,E2)
& sequential(E2,E3)
& sequential(E3,E1) ) ) ).
fof(length_defn,axiom,
! [V1,V2,P] :
( path(V1,V2,P)
=> length_of(P) = number_of_in(edges,P) ) ).
fof(path_length_sequential_pairs,axiom,
! [V1,V2,P] :
( path(V1,V2,P)
=> number_of_in(sequential_pairs,P) = minus(length_of(P),n1) ) ).
fof(sequential_pairs_and_triangles,axiom,
! [P,V1,V2] :
( ( path(V1,V2,P)
& ! [E1,E2] :
( ( on_path(E1,P)
& on_path(E2,P)
& sequential(E1,E2) )
=> ? [E3] : triangle(E1,E2,E3) ) )
=> number_of_in(sequential_pairs,P) = number_of_in(triangles,P) ) ).
fof(graph_has_them_all,axiom,
! [Things,InThese] : less_or_equal(number_of_in(Things,InThese),number_of_in(Things,graph)) ).
fof(triangles_and_sequential_pairs,conjecture,
( complete
=> ! [P,V1,V2] :
( shortest_path(V1,V2,P)
=> number_of_in(sequential_pairs,P) = number_of_in(triangles,P) ) ) ).
%--------------------------------------------------------------------------